Five warm-ups for grades 9–12. Each takes three to five minutes. Answers and teacher notes are in the collapsed box under each prompt.

ELA

In active voice, the subject does the action. In passive voice, the subject receives it, and the doer may disappear. Rewrite sentences 1–3 in active voice, inventing a doer if you need one. Then decide whether sentence 4 should stay passive, and explain why. (These examples are made up for practice.)

  1. The samples were tested by the lab technician.
  2. Mistakes were made in the report.
  3. The roof of the museum was damaged by hail.
  4. The injured hiker was carried down the mountain before sunset.
Answer and teacher notes

Answers will vary. Samples:
1. The lab technician tested the samples.
2. The editors made mistakes in the report.
3. Hail damaged the roof of the museum.
4. Passive works here. The reader cares most about the hiker, and the rescuers may be unknown or less important. An active version such as “Rescuers carried the injured hiker down the mountain before sunset” is also fine if the rescuers matter to the story.

Sentence 2 is the best discussion starter: passive voice can hide who is responsible. Ask students who benefits from “Mistakes were made.” Common mistake: calling any past-tense sentence passive. “The dog was barking” uses was but is active, because the dog is doing the action. A quick test: if you can add “by someone” after the verb, the sentence is probably passive. Passive voice isn’t wrong. Lab reports often use it because the procedure matters more than the person. Extension: find one passive sentence in a textbook and decide whether it’s the right choice.

Math

The height of a punted football, in feet, is modeled by h(t) = −16t² + 56t + 3, where t is seconds after the kick. (These numbers are made up for practice, and the model ignores air resistance.) (a) What is the height of the ball at the kick? (b) When does the ball reach its highest point, and how high is it? (c) To the nearest hundredth of a second, what is the hang time, from the kick until the ball would hit the ground? (d) For how long is the ball above 40 feet? Round to the nearest hundredth. (e) What does the −16 tell you about what’s acting on the ball?

Answer and teacher notes

(a) h(0) = 3 feet. (b) t = −b ÷ 2a = −56 ÷ (−32) = 1.75 seconds. h(1.75) = −16(3.0625) + 56(1.75) + 3 = −49 + 98 + 3 = 52 feet. (c) Solve −16t² + 56t + 3 = 0: t = (56 + √(3,136 + 192)) ÷ 32 = (56 + √3,328) ÷ 32 ≈ 3.55 seconds. (d) Solve −16t² + 56t − 37 = 0: t = (56 ± √768) ÷ 32, so t ≈ 0.884 and t ≈ 2.616. The ball is above 40 feet for about 2.616 − 0.884 = 1.73 seconds. (e) It reflects gravity pulling the ball down. It is half of the acceleration, about 32 feet per second squared.

Check on (b): the two times from (d) are the same distance from the peak: (0.884 + 2.616) ÷ 2 = 1.75. ✓ Check on (c): h(3.55) ≈ 0, within rounding. ✓ Common mistake: reporting 1.75 as the hang time. That’s the top of the flight, and the ball takes longer to come down because it started 3 feet up. Note on (d): subtracting roots already rounded to 0.88 and 2.62 gives 1.74, so accept that answer if students show the rounding. Extension: which single number in the equation would you change to model a stronger kick? (The 56, the starting upward speed.)

Science

The CDC says resistant germs survive antibiotics, multiply, and spread. Try the model. A culture holds 1,000,000,000 bacteria, and 10 of them are resistant to an antibiotic. The drug kills every cell that isn’t resistant, and the survivors double every 30 minutes. (These numbers are made up for practice.) (a) What percent of the original population survives? (b) How many doublings does it take for the survivors to reach at least 1,000,000,000, and how many hours is that? (c) What is different about the new population? (d) Did the antibiotic create the resistance in this model? Explain. (e) New guidelines in Nature Medicine cover phage therapy, which uses viruses that infect bacteria. Phages usually target specific species or strains, unlike many broad antibiotics. Give one advantage and one drawback of that narrow targeting.

Answer and teacher notes

(a) 10 ÷ 1,000,000,000 × 100 = 0.000001%. (b) 10 × 2ⁿ ≥ 10⁹, so 2ⁿ ≥ 10⁸ and n ≥ log₂(10⁸) ≈ 26.6. That means 27 doublings, or 27 × 0.5 = 13.5 hours. (c) Nearly every cell now has the resistance trait. (d) No. In this model the resistant cells were already there. The drug removed their competition. (e) Answers will vary. Advantage: it may leave helpful bacteria alone. Drawback: the phage must match the specific infection, so it takes testing and may not work on others.

Check on (b): 10 × 2²⁶ = 671,088,640, which is too small. 10 × 2²⁷ = 1,342,177,280, which is enough. ✓ This model is simplified, and the CDC notes that resistance traits can also spread between germs, even to ones that were never exposed to the drug. Keep phage therapy in perspective: the guidelines do not recommend it as a routine treatment, and the report says controlled trials haven’t yet shown how reliably it works. The report also says bacteria can change their susceptibility to phages during an infection, which connects back to (d). Extension: why might doctors combine a phage with an antibiotic rather than use one alone?

Sources: CDC: About Antimicrobial Resistance (selection, spread, gene sharing); ScienceDaily: Scientists Turn Viruses Into Weapons Against Deadly Superbugs (phages, guidelines, cautions); Britannica: Bacteriophage (definition)

Social Studies

Russia’s October Revolution took place on what most of the world called November 6–7, 1917. Russia still used the older Julian calendar, where the dates were October 24–25, a gap of 13 days. Pope Gregory XIII proclaimed the newer calendar in 1582, dropping 10 days to fix drift in the dates of the seasons. Under its rule, a century year is a leap year only if it is exactly divisible by 400. Under the Julian calendar, every century year is a leap year. Russia switched in 1918. (a) Use the leap-year rule to explain why a 10-day gap had grown to 13 by 1917. (b) What is today’s date on the Julian calendar? (c) Why does a historian need to state which calendar a date comes from? (d) Russia switched more than 330 years after the new calendar was proclaimed. Besides science, what might shape a country’s decision to change its calendar? (e) Britannica’s explainer says November 6–7, but its timeline says November 7–8. Use the 13-day gap to decide which date pair fits October 24–25.

Answer and teacher notes

(a) 1700, 1800, and 1900 were leap years on the Julian calendar but not the Gregorian one, since none divides evenly by 400. That adds 3 days: 10 + 3 = 13. (b) November 6 − 13 days = October 24, because 2000 was a leap year in both calendars and the gap is still 13. (c) Answers will vary: the same event can have two dates, so readers could mix up the order of events. (d) Answers will vary: religion, tradition, trade, and who holds power. (e) October 24 + 13 = November 6 and October 25 + 13 = November 7, so November 6–7 fits.

The timeline says the Bolsheviks deposed the provisional government and declared that power had passed to the soviets. Keep the focus on the calendar and on how historians handle sources, not on judging the revolution. Common mistake on (a): counting 1600, which was a leap year on both calendars. Check on (e): both Britannica pages agree the Julian dates were October 24–25, so the mismatch is in the conversion. NVCC’s notes also pair October 25 with November 7. ✓ Extension: when will the gap grow to 14 days? (After the Julian leap day in 2100, since 2100 isn’t divisible by 400.)

Sources: Britannica: Why Is It Called the October Revolution? (dates, 13-day gap); Britannica: Russian Revolution Timeline (events, November 7–8); Britannica: Gregorian Calendar (1582, 10 days, leap-year rule); NVCC: Notes on the Russian Calendar (1918 change)

Current Events

Astronomers have long tried to explain why the red supergiant Betelgeuse behaves strangely. A study in The Astronomical Journal, reported November 3, offers new evidence for a hidden companion star called Siwarha. The companion is estimated to orbit at only about twice Betelgeuse’s radius, and it is tens to hundreds of times too faint to detect directly in these radio data. So the team looked for its effect instead. Using the VLA and ALMA radio observatories from 2021 to 2026, at frequencies from 22 GHz to 485 GHz, they found that Betelgeuse tends to look more stretched when the companion should be farthest from it on the sky. An earlier proposal linked the companion to a brightness cycle of about 2,100 days. (a) Convert 2,100 days to years. Could observations from 2021 to 2026 cover one full cycle? (b) Using c ≈ 3 × 10⁸ m/s, find the wavelengths of 22 GHz and 485 GHz. (c) How can scientists gather evidence for something they can’t see directly? (d) The report calls this compelling evidence but also says more observations are needed. How can both be true? (e) What result in future observations would weaken the companion idea?

Answer and teacher notes

(a) 2,100 ÷ 365.25 ≈ 5.75 years. The observations span about 5 years, so they may not cover a full cycle. (b) λ = c ÷ f. 22 GHz: 3 × 10⁸ ÷ 2.2 × 10¹⁰ ≈ 1.4 cm. 485 GHz: 3 × 10⁸ ÷ 4.85 × 10¹¹ ≈ 0.62 mm. (c) Answers will vary: they look for effects on nearby matter and check whether those effects match a prediction. (d) Answers will vary: evidence can point strongly toward an explanation without finally proving it. (e) Answers will vary: if the stretching stopped tracking the companion’s predicted position, the link would weaken.

Check on (b): frequency went up by about 22 times, and wavelength went down by the same factor (14 mm ÷ 0.62 mm ≈ 22). ✓ Common mistake on (b): forgetting that GHz means 10⁹ Hz. The 2,100-day cycle is a brightness cycle, and the report doesn’t state it as a measured orbital period, so ask students to keep the two ideas separate. The report says the wake is a modeled explanation rather than a direct image. Have students list the hedging words in the report, such as “may,” “believed,” and “suggests.” Extension: why would observing many points along the orbit make this result stronger?

Source: ScienceDaily: A Hidden Star Is Plowing Through Betelgeuse’s Atmosphere, New Evidence Suggests (Siwarha, observations, evidence, cautions, 2,100-day cycle)

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